Question

The kinetic energy of a cat running with a speed of 10m/s is 500 J . Find the kinetic energy of the cat :
i) If the speed is doubled
ii) If the speed is tripled

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Answer 1

1/2mv² = 500J

v = 10m/s

Thus,

1/2*m*10²= 500

m = 10kg

Now speed is doubled

So

v = 20m/s

K.E = 1/2mv²

= 1/2*10*20*20

= 2000J

Now speed is tripled

so v = 30m/s

K. E = 1/2mv²

= 1/2* 10*30*30

= 4500J

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Answer 2

Answer:

i)2000J

ii)32000J

Explanation:

kinetic energy =500j

and velocity = 10m/s

let mass =m

then kinetic energy =1/2 × m × v square

500 =1/2×m×10×10

500=50m

500/50=m

10kg=m

1. if velocity is doubled

then

k=1/2 m×v square

k=1/2×10×20×20

k=2000J

2. if velocity is increased 8 times

then

k =1/2m×v square

k=1/2×10×80×80

k=5×6400

k=32000J