The kinetic energy of a cat running with a speed of 10m/s is 500 J . Find the kinetic energy of the cat :
i) If the speed is doubled
ii) If the speed is tripled
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Answers
Answered by
14
1/2mv² = 500J
v = 10m/s
Thus,
1/2*m*10²= 500
m = 10kg
Now speed is doubled
So
v = 20m/s
K.E = 1/2mv²
= 1/2*10*20*20
= 2000J
Now speed is tripled
so v = 30m/s
K. E = 1/2mv²
= 1/2* 10*30*30
= 4500J
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Answered by
2
Answer:
i)2000J
ii)32000J
Explanation:
kinetic energy =500j
and velocity = 10m/s
let mass =m
then kinetic energy =1/2 × m × v square
500 =1/2×m×10×10
500=50m
500/50=m
10kg=m
1. if velocity is doubled
then
k=1/2 m×v square
k=1/2×10×20×20
k=2000J
2. if velocity is increased 8 times
then
k =1/2m×v square
k=1/2×10×80×80
k=5×6400
k=32000J
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