Question

The Kinetic energy of a charged particle decrease by 10J as it moves from a point at potential 100V to a point At potential 200 V. find the Charge on the particle.​

Answer 1

Answer: 0.1C

Explanation:

E = mc2 = qV = q100

Q = 10/100 = 0.1C

Answer 2

$\textbf{Hey there!}\\\\ \sf Given,\\ \text{Change in Kinetic Energy} (\Delta K.E) = 10 \ J\\\text{Change in Potential }\Delta V = 200 \ V - 100 \ V$

$\sf \text{From Work Energy- Theorem,}\\\Delta K.E = q \Delta V\\10 = q (200-100)\\q = \frac{10}{100}\\\\\boxed{\boxed{q = 0.1 \ C}}$

$\textbf{Hence the charge on the particle is 0.1 C.}$