the kinetic energy of a particle varies according to the relation k= Av2÷ (B+x2). here x is the distance and v it's velocity. dimensional formula of AB is
Answers
Explanation:
GiveN:-
A father is 7 times as old as his son, two years ago the Father was 13 times as old as his son.
To FinD:-
The present age of son.
SolutioN:-
Let the present age of the son be x years.
Let the present age of the father be 7x years.
2 years ago their ages were:-
Son = (x - 2) years.
Father = (7x - 2) years.
It is said that two years ago the Father was 13 times as old as his son.
According to the question,
\large\implies{\sf{7x-2=13(x-2)}}⟹7x−2=13(x−2)
\large\implies{\sf{7x-2=13x-26}}⟹7x−2=13x−26
\large\implies{\sf{-2+26=13x-7x}}⟹−2+26=13x−7x
\large\implies{\sf{24=6x}}⟹24=6x
\large\implies{\sf{\dfrac{24}{6}=x}}⟹
6
24
=x
\large\implies{\sf{\dfrac{\cancel{24}}{\cancel{6}}=x}}⟹
6
24
=x
\large\implies{\sf{4=x}}⟹4=x
\large\therefore\boxed{\bf{x=4.}}∴
x=4.
Their present ages:-
Son's age = x = 4 years.
Father's age = 7x = 7 × 4 = 28 years.
The present age of the son is 4 years.
Explanation:
A(LT ¹-)²/B+L²
=ML⁴T⁰ (Here x is given as distance so L and v is given as velocity so V =L T power minus 1