Question

The kinetic energy of a system in laboratory system as compared to that in the centre of mass system is always…….​

Answer 1

Answer:

The kinetic energy of the center of mass (i.e. modeling the system as a point particle with all of its mass concentrated at its center of mass) is called translational kinetic energy.

Answer 2

Answer:

The kinetic energy of a system in a laboratory system as compared to that in the center of the mass system is always more.

Explanation:

• In the center of the mass frame, the kinetic energy includes only rotational kinetic energy. Which is given as,

$\mathrm{K.E.=\frac{1}{2}I\omega^2 }$          (1)

Where,

K.E.=kinetic energy of the center of the mass frame

I=moment of inertia of the body

ω= rotational velocity of the body

• In the laboratory system, the kinetic energy includes both rotational and translational kinetic energy. Which is given as,

$\mathrm{K.E.=\frac{1}{2}I\omega^2+\frac{1}{2}Mv^2 }$       (2)

Where,

K.E.=kinetic energy of the laboratory system

M=mass of the body

v=velocity with which the body is moving

So, the kinetic energy of a system in a laboratory system as compared to that in the center of the mass system is always more.

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