Question

the kinetic energy of an electron in second sale of an hydrogen atom is 40 ev then what will be the total energy of electron in its third shell?​

Answer 1

Answer:

-17.77 eV the total energy of electron in its third shell.

Explanation:

$T.E_n = P.E._n(negative)+K.E_n(positive)$

K.E =$\frac{1}{2}$P.E

$T.E_n =\frac{-1}{2}P.E._n=-13.6\times \frac{Z^2}{n^2}eV$

$T.E_n$= Total energy of an electron $n^{th}$ orbit

$P.E_n$ = Potential energy of an electron $n^{th}$ orbit

$K.E_n=13.6\times \frac{Z^2}{n^2}ev$

$K.E_n$ =Kinetic  energy of $n^{th}$ orbit

n = number of orbit

Z = atomic number

Kinetic energy of an electron in second state = 40 eV

$K.E_2=40 eV=3.6\times \frac{Z^2}{2^2}eV$

$Z^2=44.444$

Total energy of an electron in an third sheell:

n= 3

$Z^2=44.444$

$T.E=-3.6\frac{44.444}{3^2} eV=-17.77 eV$