Physics, asked by mayrasanchez1608, 1 year ago

The kinetic energy of an electron revolving around a nucleus will be
(a) Four times of P.E.(b) Double of P.E.(c) Equal to P.E.(d) Half of its P.E.

Answers

Answered by Anonymous
2

Answer:

Explanation:

The energy of an electron in n = n is En= - 13.6/ n² eV for the hydrogen atom.  In the Bohr's theory we always come across the result as -

En= (1/2)( potential energy).

Therefore, (1/2)(potential energy )=-(13.6/9)eV

Therefore, the potential energy = -27.2/9 eV

KE of electron =13.6Z²/ n²eV  

PE of electron = 2×13.6Z²/n²eV  

Therefore,

KE of electron = 1/2×PE of electron

Thus, The kinetic energy of an electron revolving around a nucleus will be half of its P.E.

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