the kinetic energy of an object of mass cm2 moving with
a velocity of 5 m/s is 25 J. What will be its kineatic
energy when its velocity is doubled? what will be its kinetic
energy when it's velocity is increased three times.
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Answer: 225 J
Explanation: The K.E (KINETIC ENERGY) of the object is 25 J.
So,
25=1/2*m*(5)2
Therefore, m = 2 kg.
Now, when the velocity is doubled, velocity becomes=2*5=10 m/s(ms-1)
So,
K.E.=1/2*2*(10)2 =100 J.
Now, when the velocity is increased three times, the velocity will be = 3*5=15m/s
Therefore, K.E. = 1/2*2*(15)2 = 225 joules/J
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