The kinetic energy of an object of mass, m moving with a velocity of 5 m s–1 is 25 J. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times?
NCERT Class IX
Sciences - Main Course Book
Chapter 11. Work and Energy
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4
K. E. = 1/2 m v^2 = 1/2 * m 5^2 = 25 Joules
=> m = 2 kg
When the velocity becomes double: ie., 10 m/s
K. E. = 4 times previous value = 4 * 25 J = 100 J
or, 1/2 m v^2= 1/2 * 2 kg * 10^2 Joules = 100 Joules
v = 3 times = 15 m/s
KE will become 9 times original value ,as KE is proportional to the square of the velocity
K. E. = 1/2 m v^2 = 1/2 * 2 kg * 15^2 = 225 Joules
=> m = 2 kg
When the velocity becomes double: ie., 10 m/s
K. E. = 4 times previous value = 4 * 25 J = 100 J
or, 1/2 m v^2= 1/2 * 2 kg * 10^2 Joules = 100 Joules
v = 3 times = 15 m/s
KE will become 9 times original value ,as KE is proportional to the square of the velocity
K. E. = 1/2 m v^2 = 1/2 * 2 kg * 15^2 = 225 Joules
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12
100J
225J
Solution :-
Given :
Kinetic energy of the object = 25 J
Velocity of the object, v = 5 m/s
To Find :
Kinetic energy when its velocity is doubled = ?
Kinetic energy when its velocity is tripled = ?
Solution :
First, we will calculate the mass 'm ' of the object.
We know,
So,
1
Now, if the velocity is doubled,
= 2 × 5
∴ 10 m/s
Kinetic energy when its velocity is doubled,
:
Therefore,if the velocity is doubled its kinetic energy is equal to 100J
Now, if the velocity is doubled,
= 3 × 5
∴ 15 m/s
Kinetic energy when its velocity is tripled,
Therefore,if the velocity is tripled its kinetic energy is equal to 225J
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