Question

The kinetic energy of an object of mass m moving with a velocity of 5m/s is 25j. What will be the kinetic energy when it's velocity is doubled ​

Answer 1

Answer:

225 joules

Explanation:

Let the mass be m

v = 5m/s

K.E = 25 J

K.E = 1/2 mv^2

25 = 1/2 m (5)^2

25 x 2 = 25m

m = 2 kg

Now if the velocity becomes 3 times then the velocity is 3 x 5 = 15m/S

Now new K.E = 1/2 x 2 x 15^2

= 225 J

Answer 2

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ANSWER :

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The mass of the object, m = m kg

The speed of the object, v = 5 m/s

The Kinetic Energy, K.E = 25 J

We know that ,

$kinetic \: energy = \frac{1}{2} mv ^{2}$

From this ,,,

Kinetic Energy ,K.E = 1/2 × m× (5)^2

25 = 1/2 × m × 25

m = 2 kg

Now the Velocity of the object is doubled.

v2 = 2v1

= 2( 5)

v2 = 10 m/s

Kinetic Energy, K.E = 1/2 × m × (v2)^2

= 1/2 × 2 × 10^2

= 100 J

The Kinetic Energy is 100 J.

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