Question

the kinetic energy of an object of mass M moving with a velocity of 5 m s-1 is 25 j.what will be its kinetic energy when its velocity is doubled what will be its kinetic energy when its velocity is increased three times​​

Answer 1

Explanation:

Let the mass be m

v = 5m/s

K.E = 25 J

K.E = 1/2 mv^2

25 = 1/2 m (5)^2

25 x 2 = 25m

m = 2 kg

Now if the velocity becomes 3 times then the velocity is 3 x 5 = 15m/S

Now new K.E = 1/2 x 2 x 15^2

= 225 J

Answer 2

Answer:

It's so simple

K.E=1/2mv^2

25J=1/2m5ms^1×5ms^1

25J×2/5×5=m

2=m

When it's velocity is increase three times

V=10m^1

K.E =1/2mv^2

K.E =1/2×2kg×15×15

K.E=225J

Explanation: