Question

The kinetic energy of an object of mass, m moving with a velocity of 5 ms−1 is 25 . What will be its kinetic energy when its velocity is doubled?

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Answer 1

Answer:

$kinetic \: energy = \frac{1}{2} \times m {v}^{2}$

K.E = 25 J V = 5 m/s m = ?

25 = 1/2 × m × 5 × 5

2 × 25 = m × 25

mass = 2 kg

If velocity get doubled

v = 10 m/s m = 2 kg

K.E = 1/2 × 2 × 10 × 10

K.E = 100 J

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Answer 2

Answer:

Therefore, its kinetic energy becomes 4 times its original value, because it is proportional to the square of the velocity. Hence, kinetic energy = 25 × 4 = 100 J.