Question

The kinetic energy of an object of mass m moving with a velocity of 5ms is 25j what will be it's kinetic energy it's velocity is doubled what will be it's kinetic energy when it's velocity in increased three times
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Answer 1

Correct question:-

The kinetic energy of an object of mass m, moving with a velocity of 5m/s is 25J. What will be it's kinetic energy when it's velocity is doubled. What will be it's kinetic energy when it's velocity is increased three times?

Given:-

→Mass of the object = m

→Velocity of the object = 5m/s

→Kinetic energy of the object = 25J

To find:-

→Kinetic energy of the body when

velocity is doubled

→Kinetic energy of the body when

velocity is increased three times.

Solution:-

Firstly,let's calculate mass of the object.

K.E. = 1/2mv²

=>1/2×m×(5)² = 25

=>25m/2 = 25

=>25m = 25(2)

=>25m = 50

=>m = 50/25

=>m = 2kg

When velocity is doubled:-

If velocity of the object is doubled, it becomes 2×5 = 10m/s

=>K.E. = 1/2×2×(10)²

=>K.E. = 100J

When velocity is increased 3 times:-

If velocity of the object is increased three times,then it becomes 3×5 = 15m/s

=>K.E. = 1/2×2×(15)²

=>K.E. = 225J

Thus:-

•Kinetic energy of the body is 100J ,when the velocity is doubled.

•Kinetic energy of the body is 225J, when the velocity is increased three times.

Answer 2

Explanation:

Correct question:-

The kinetic energy of an object of mass m, moving with a velocity of 5m/s is 25J. What will be it's kinetic energy when it's velocity is doubled. What will be it's kinetic energy when it's velocity is increased three times?

Given:-

→Mass of the object = m

→Velocity of the object = 5m/s

→Kinetic energy of the object = 25J

To find:-

→Kinetic energy of the body when

velocity is doubled

→Kinetic energy of the body when

velocity is increased three times.

Solution:-

Firstly,let's calculate mass of the object.

K.E. = 1/2mv²

=>1/2×m×(5)² = 25

=>25m/2 = 25

=>25m = 25(2)

=>25m = 50

=>m = 50/25

=>m = 2kg

When velocity is doubled:-

If velocity of the object is doubled, it becomes 2×5 = 10m/s

=>K.E. = 1/2×2×(10)²

=>K.E. = 100J

When velocity is increased 3 times:-

If velocity of the object is increased three times,then it becomes 3×5 = 15m/s

=>K.E. = 1/2×2×(15)²

=>K.E. = 225J

Thus:-

•Kinetic energy of the body is 100J ,when the velocity is doubled.

•Kinetic energy of the body is 225J, when the velocity is increased three times.

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