the kinetic energy of an object of mass m moving with a velocity of 5m s is 25j what will be its kinetic energy when its velocity is increased three times
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If the velocity of an object is doubled, then its kinetic energy becomes 4 times the original value, because it is proportional to the square of the velocity. Hence, kinetic energy = 25 × 4 = 100 J. ... Hence, kinetic energy = 25 × 9 = 225 J.
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Answer:
given kinetic energy = 25J
velocity = 5m/s
therefore, let mass be = x
=> ½mv² = 25
=> m/2 = 25/25
=> m = 2kg
therefore, if the velocity is tripled ,
then velocity = 15m/s
therefore kinetic energy = ½mv²
= 2×225/2
= 225J
so, difference between final and initial energy
= 225/25
= 9times the initial energy.
Hence the energy increases by 9 times the initial energy.
Hope it helped :)
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