Question

the kinetic energy of an object of mass m moving with a velocity of 5m s is 25j what will be its kinetic energy when its velocity is increased three times

Answer 1

Answer:

Answer = 225J

Explanation:

We know that Kinetic Energy (KE) = $\frac{1}{2}mv^{2}$

$v_{i}$ = initial velocity

$\frac{1}{2}m(v_{i})^{2} = 25J\\\\\frac{1}{2}m(5)^{2} = 25\\\\m = 2kg$

final velocity = $v_{f}$ = 15$ms^{-1}$

final KE = $\frac{1}{2}(2)(15)^{2} = (15)^{2} = 225J$

Answer = 225 J might help Thanks!