Question

The kinetic energy of an object of mass, m moving with a velocity of 5m/s is 25 J. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times?

Answer 1

Explanation:

If velocity increased by 2 times the kinetic energy increases 4 times

So in first case kinetic energy,

K. E =25 x 4

=100 J

If velocity increases by 3 times then K. E is,

=9 x 25

=225 J

Answer 2

Explanation:

From the question

↪ Given

Velocity = 5m/sec

Kinetic energy of an object = 25J

mass = m kg

Kinetic Energy [K.E] = ½mv²

25 = ½×m×(5)²

25 = ½×m×25

m = 2kg

when velocity is doubled

v = 2×5 = 10m/sec

K.E = ½×2×10²

K.E = 100J

when velocity increased thrice

v = 3×5 = 15m/sec

K.E = ½×2×15²

K.E = 225J

❤Brainliest-Thanks❤