The kinetic energy of an object of mass "M" moving with a velocity of 5m/s¹ is 25 joule. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times?
Answers
Explanation:
{ \huge{ \green{ \underline{ \frak{To \: \: Given} } \colon}}}ToGiven:
{ \large{ \red{➟ \: \: \sf{Mass = 5 \: m/s}}}}➟Mass=5m/s
{ \large{ \blue{➟ \: \: \sf{Velocity = 5 \: m/s}}}}➟Velocity=5m/s
{ \large{ \pink{➟ \: \: \sf{K.E = 25 \: \: joules}}}}➟K.E=25joules
{ \huge{ \blue{ \underline{ \frak{To \: \: Find} } \colon}}}ToFind:
{ \large{ \purple{✮ \: \: \underline{ \underline{ \bf{Part \: \: i \: = \: K.E \: \: when \: \: when \: \: velocity \: \: is \: \: doubled}}}}}}✮Parti=K.Ewhenwhenvelocityisdoubled
{ \large{ \purple{✮ \: \: \underline{ \underline{ \bf{Part \: \: ii \: = K.E\: when \: \: velocity \: \: is \: \: tripled}}}}}}✮Partii=K.Ewhenvelocityistripled
{ \large{ \pink{⇝ \: \boxed{ \tt{K.E = \frac{1}{2} mv {}^{2} }}}}}⇝K.E=21mv2
{ \large{ \red{ ➟ \: \: \bf{25 = \dfrac{1}{2} m5 {}^{2} }}}}➟25=21m52
{ \large{ \red{ ➟ \: \: \bf{m = \cancel \dfrac{25}{25} \times 2}}}}➟m=2525×2
{ \large{ \green{ \therefore{ \tt{mass \: = \: 2 \: kg}}}}}∴mass=2kg
{ \huge{ \orange{ \underline {\frak{Solution \: \: i}} \colon}}}Solutioni:
{ \large{ \pink{➞ \: \: \sf{ K.E = \dfrac{1}{ \cancel{2} }\times{ \cancel 2} \times 10 {}^{2} }}}}➞K.E=21×2×102
{ \large {\bf{ \pink{ \therefore{K.E = { \boxed{ \sf{100 \: joules}}}Ans.}}}}}∴K.E=100joulesAns.
{ \huge{ \orange{ \underline {\frak{Solution \: \: ii}} \colon}}}Solutionii:
{ \large{ \red{➞ \: \: \sf{K.E = \dfrac{1}{ \cancel{2}} \times { \cancel{2}} \times 15 {}^{2} }}}}➞K.E=21×2×152
{ \large{ \red{ \therefore{ \sf{K.E \: = { \boxed{ \sf225 \: \: joules}}}Ans.}}}}∴K.E=225joulesAns.
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