Question

The kinetic energy of an object of mass, m moving with a velocity of 5 ms^-1 is 25 J. What will
be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its
velocity is increased three times?​

Answer 1

Answer:

Kinetic energy=25J

velocity=5m/s

K.E.=1/2 mv²

25=1/2×m×5²

m=2kg

Kinetic energy when velocity is doubled= 1/2×2×10²=100J

Kinetic energy when velocity is increased three times=1/2×2×15²=225J