The kinetic energy of an object of mass m, moving with a velocity of 5 m/s is 25 J. What will be its kinetic energy when its speed is doubled? it is given here doubled not tripled ?
koi hai ? -_-"
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Answer: 100J
Step-by-step explanation:
Let the initial kinetic energy be K.E1 and final be K.E2.
Initial velocity be V1 and final be V2.
We know,
kinetic energy= ½×m×V² . According to the question V2= 10m/s , V1= 5m/s therefore square of V1 = 25 and that of V2= 100.
K.E1 = 25J, we have to find out K.E2.
Refer to the attachment for the next step.
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