Question

The kinetic energy of an object of mass, m moving with a velocity of 5 ms' is 25 J. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times? ​

Answer 1

Answer:

75 joule

Explanation:

kinetic energy= 1/2×m×(5)^2

25 = 1/2×m×25

25×2\25 = m

m = 2kg.

now according to question---

kinetic energy = 1/2 ×2×3(5)^2

= 75 joule

Answer 2

Answer:

The kinetic energy of an object of mass, m moving with a velocity of 5 ms' is 25 J. Then its kinetic energy when its velocity is doubled, and also tripled is

Explanation:

Kinetic energy = 1/2 mv^2

m = mass of the object

v = velocity of the object

Given,

K.E = 25J

v = 5m/s

25 = 1/2 × m × 5^2

m = 50/25 = 2kg

Now we can find the kinetic energy when velocity doubles, v = 10m/s

K.E = 1/2×2× 10^2 = 100J

When velocity increases by three times, v = 15m/s

K.E = 1/2×2×15^2 = 225J