The kinetic energy of an object of mass M moving with a velocity V metre per second is 25 June what will be its kinetic energy when its velocity is doubled
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If velocity is doubled, its kinetic energy is times.
Because KE=1/2mv^2=25j
again, KE=1/2m(2v)^2
=4×1/2mv^2
=4×25
=100j
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Because KE=1/2mv^2=25j
again, KE=1/2m(2v)^2
=4×1/2mv^2
=4×25
=100j
Please mark it as brainliest answer..
I work hard for this... please
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