Question

the kinetic energy of an object of mass M moving with a velocity 5ms-¹ is 25 J. what will be it's kinetic energy when it's it's velocity is doubled ​

Answer 1

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$ke = \frac{1}{2} m {v}^{2} \\ 25 = \frac{1}{2} \times m \times 25 \\ m = 2kg \\ \\ now \\ v = 2v \\ \\ k.e = \frac{1}{2} m {v}^{2} \\ ke = \frac{1}{2} \times 2 \times 100 \\ ke = 100j$

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Answer 2

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ANSWER :

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The mass of the object, m = M kg

The speed of the object, v = 5 m/s

The Kinetic Energy, K.E = 25 J

We know that ,

$kinetic \: energy = \frac{1}{2} mv ^{2}$

From this ,,,

Kinetic Energy ,K.E = 1/2 × m× (5)^2

25 = 1/2 × M × 25

M = 2 kg

Now the Velocity of the object is doubled.

v2 = 2v1

= 2( 5)

v2 = 10 m/s

Kinetic Energy, K.E = 1/2 × m × (v2)^2

= 1/2 × 2 × 10^2

= 100 J

The Kinetic Energy is 100 J.

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