Question

The kinetic energy of an object of mass, m moving with a velocity of 5 ms-1 is 25 J. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times?

Answer 1

As we know

$ke = \frac{1}{2} \times mass \times {velocity}^{2}$

In First Case

KE=25J

Velocity=5m/s

Mass of Object=m

$\frac{1}{2} \times m \times 5 {}^{2} = 25 \\ \\ \frac{1}{2} \times m \times 25= 25\\ \\ m = 25 \times \frac{2}{25} \\ \\ m = 2$

Mass=2 kg

In second Case, Velocity is Doubled

Velocity in first case=5 m/s

Velocity in Second Case=5×2=10 m/s

Velocity=10 m/s

Mass=2 kg

$ke = \frac{1}{2} \times m \times {v}^{2} \\ \\ ke = \frac{1}{2} \times 2 \times {10}^{2} \\ \\ ke = \frac{1}{2} \times 2 \times 100 \\ \\ ke = 100j$

KE=100J

In Third Case Velocity is Increased by 3 times

Velocity in First Case=5 m/s

Velocity in Third Case=5×3=15 m/s

Velocity=15 m/s

Mass=2 kg

$ke = \frac{1}{2} \times m \times {v}^{2} \\ \\ ke = \frac{1}{2} \times 2 \times {15}^{2} \\ \\ ke = {15}^{2} \\ \\ ke = 225j$

KE=225J

Answer We Got

KE=100J

KE=225J

Answer 2

Answer:

i

Explanation:

KE=100J

KE=225J

is the ans hope it will help you thank u