The kinetic energy of electron emitted by
a metal sheet of work function 5eV when
photons from EMR of wavelength 62nm
strike the metal plate is:(with proper steps)
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Answer:
Explanation:
The wavelength of the electron emitted by a metal sheet of work function 5 eV when photons from EMR of wavelength 62 nm strike the metal plate .
For metal A,
de-broglie wavelength (λ
A
)=
mv
A
h
−−−−−−1
⇒V
A
=
mλ
A
h
4.25−W
A
=
2
1
×m×
m
2
×A
2
h
2
⇒4.25−W
A
=
2mλA
2
h
2
−−−−−−2
For metal B,
4.7−W
B
=
2mλ
A
2
h
2
−15−−−−−3
and λ
B= mv
B
h
⇒2λ
A
=
mv
Bh
⇒V
B= 2mλ -A h
−−−−−4
So,
from difference in kinetic energy,
⇒−T
B+T
A =1.5−−−−x
and solving (i),(ii),(iii),(iv) and (v) simultaneously we find, W
A
=2.25eV
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