Question

The Kinetic energy of one electron is 2.8 x 10-13 J. The de-Broglie wavelength is
(A) 9.25 x 10-13 m
(B) 9.25 x 10-16m
(C) 9.25 x 10-8m
(D) 18.5 x 10-13 m​

Answer 1

Answer:

The answer is a option C

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Answer 2

Answer :

Kinetic energy of electron = 2.8×10‾¹³J

We have to find de-broglie wavelength associated with electron$.$

de-Broglie equation :

• λ = h / √(2mK)

λ denotes wavelength

m denotes mass

K denotes kinetic energy

h denotes plank's constant

$\circ\:\sf{\lambda= \dfrac{6.6\times10^{-34}}{\sqrt{2\times 9.1\times 10^{-31}\times 2.8\times 10^{-13})}}}$

$\circ\sf\:\lambda=\dfrac{6.6\times 10^{-34}}{\sqrt{50.94\times 10^{-44}}}$

$\circ$ λ = (6.626×10‾³⁴)/(7.13×10‾²²)

$\circ$ λ = 9.25 × 10‾¹³ m

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