Question

The kinetic energy of the electron in an orbit of radius r in hydrogen atom is (e = electronic charge)

Answer 1

Given:

The kinetic energy of electron radius r.

To find:

The kinetic energy of the electron of the hydrogen.

Solution:

Let U be the potential energy of the electron.

U= -$\frac{e^{2} }{r}$

Now to get the kinetic energy, we need to put

K.E=$\frac{1}{2}$P.E

=$\frac{1}{2}$$\frac{e^{2} }{r}$

The required K.E of the hydrogen atom is $\frac{1}{2} \frac{e^{2} }{r}$