The kinetic energy per cubic metre of a perfect gas at N.T.P. is (Take atmospheric pressure = 1 x 105 N/m2)
1) 1.5 x 105 J/m3 2) 2 x 105 J/m3
3) 0.75 x 105 J/m3 4) 2.5 x 105 J/m3
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question : The kinetic energy per cubic metre of a perfect gas at N.T.P. is.
1) 1.5 × 10^5 J/m³ 2) 2 × 10^5 J/m³
3) 0.75 × 10^5 J/m³ 4) 2.5 × 10^5 J/m³
solution : according to kinetic theory of gas, P exerted by a gas of density ρ and r.m.s velocity v is given by, P = 1/3 ρv² .........(1)
and also average translational kinetic energy per unit volume is given by, E = 1/2 ρv² .......(2)
[ as kinetic energy , K.E = 1/2 mv² = 1/2 ρV v²
and then kinetic energy per unit volume, E = 1/2 ρv² ]
from equations (1) and (2) we get,
P/E = 2/3
⇒E = 3P/2 = 3 × 1 × 10^5/2 = 1.5 × 10^5 N/m²
Therefore kinetic energy per unit volume is 1.5 × 10^5 N/m² .
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