Question

The kinetic energyof he and ne at 25°C is?

Answer 1

Answer:

Well the answer of your question is " 6.2 * 10^-21 J "

Actually the average kinetic energy can easily be determined by the formula :

3/2 KT . Here K is the boltzmann constant which is equal to 1.38x10^-23 J/K

and T representing the temperature in kelvin

25 degree celsius = 298 kelvin so by just putting the values in the formual

Average kinetic energy = 3/2 × 1.38x10^-23 × 298 = 6.2 * 10^-21 J

So the answer will be 6.2 * 10^-21 J