Question

The king queen and jack of club are removed from a deck of 52 playing cards and then well shuffled. One card is drawn at random from the remaining cards.find the probability of getting 1. A king 2.the 10 of hearts.

Answer 1

Heya !
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★Probability ★
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=> Deck consists of 52 cards :

★ 4 Kings , 4 Queens , 4 Jacks

→ When King , Queen and Jack of club are removed , we are left with ★ 3 Kings , 3 Jacks and 3 Queens. Also ,

=> Cards remaining = 52 - 3

=> 49 ............[ Total Outcomes ]

★ A card is drawn at random :
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1. ] P ( a king )

=> We know ,

•°• Probability = Favourable Outcomes / Total Outcomes

→ Total Outcomes = 49

→Favourable Outcomes = 3 ( as 1 king is removed )

=> P ( a king ) = 3 / 49 ✔

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2. ] P ( a ten or Hearts )

=> We know ,

•°• Probability = Favourable Outcomes / Total Outcomes

→Total Outcomes = 49

→Favourable Outcomes = 1

=> P ( Ten of Hearts ) = 1 / 49 ✔

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$....$

Answer 2

$Hey\:!!..$

The answer goes here....

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》To find -

Find the probability of getting -

1. A king

2. The 10 of hearts.

》Given -

King, Queen and Jack of club is removed.

》Solution -

A deck of cards contain 52 cards. A deck contains 4 Queen, 4 King and 4 Jacks.

And the deck contains 4 ranks - clubs (♧), diamond (◇), spades (♤) and hearts (♡).

Since, one king, one queen, and one jack is removed. Therefore we have total 3 kings, 3 queen and 3 jacks left.

Also, the total card left is $52-3=49.$

Now, the probability of getting a king -

⇒ $\frac{No.\:of\:possible\:outcomes}{Total\:outcomes}$

⇒ $\frac{3}{49}$

So, the probability of getting a king is $\frac{3}{49}$ .

Now, the probability of getting 10 of hearts -

⇒ $\frac{No.\:of\:possible\:outcomes}{Total\:outcomes}$

⇒ $\frac{1}{49}$

So, the probability of getting a 10 of hearts is $\frac{1}{49}$ .

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Thanks !!..