The king, queen and jack of clubs are removed from a pack of 52 cards and then the remaining cards are well shuffled. A card is selected from the remaining cards. Find the probability of getting a card (i) of spade (ii) of black king (iii) of club (iv) of jacks
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Answered by
63
Answer:Number of possible outcomes = 52 - 3 = 49
Probability ( of an event ) = No. of favorable outcome / No. of possible outcome
i) No . of favourable outcomes = 13
Probability of getting a card of spade = 13/49
ii)No. of favourable outcomes = 1
Probability of getting a black king = 1 / 49
iii)No. of favourable outcomes = 10
Probability of getting a card of club = 10/49
iv)No. ffavourable outcomes = 3
Probability of getting a jack = 3/49
Answered by
7
Step-by-step explanation:
The king, queen and jack of clubs are removed from a deck
⇒ Number of cards left =52−3=49
Total number of clubs left in deck =13−3=10
Probability of getting a club = Number of clubs left in deck ÷ Total number of cards left
=
49
10
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