Question

The king, queen and jack of clubs are removed from a pack of 52 cards and then the remaining cards are well shuffled. A card is selected from the remaining cards. Find the probability of getting a card (i) (ii) (iii) (iv) of spade of black king of club of jacks

Answer 1

As the face cards of clubs are removed, the total no. of cards is 52 - 3 = 49. This is the total no. of outcomes.

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(i) No. of spades is 13 there, and no spades card is removed. So probability = 13/49.

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(ii) After removal, there'd be one black king only, i.e., spades king. So probability = 1/49.

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(iii) After removal, there'd be 13 - 3 = 10 clubs cards only. So probability = 10/49.

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(iv) After removal, there'd be 3 jacks only. So probability = 3/49.