Math, asked by Divksion, 9 months ago

The king queen and Jack of the suite are removed from a deck of 52 cards. One card is selected from the remaining cards. Find the probability of getting a queen, a spade, a heart card bearing the number 5


Answers

Answered by naveen5616
4

Answer:

qeen is equal to=number of outcomes by total number of outcomes =total number of outcomes is equal to 44. =number of outcomes for qeen is equal to zero. =0.44 heart no.5=1/44 = spades=12/44

Answered by JeanaShupp
2

The P(Queen ) = 0 , P(spade)= \dfrac{1}{4} and P(5 of heart )= \dfrac{1}{40}

Step-by-step explanation:

Total cards = 52

Cards removed

Numbers of king = 4

Number of queen = 4

Number of jack = 4

Total cards removed = 4+4+4 = 12

remaining cards = Total cards - Removed cards = 52 - 12= 40

Now as we know probability is given by

\text {P(E)}=\dfrac{\text {Sum of observations }}{\text {Total number of observations} } where P(E) is the probability of an event

Therefore

Number of queen = 0

P(queen) = \dfrac{\text {Number of queen }}{\text {Total cards}} =\dfrac{0}{40} =0

Number of spades = total spades - removed cards of spades = 13-3 = 10

P(spade) = \dfrac{\text {Number of spade }}{\text {Total cards}} =\dfrac{10}{40} =\dfrac{1}{4}

Number of 5 of heart = 1

P( 5 of heart) = \dfrac{\text {Number of 5 of heart }}{\text {Total cards}} =\dfrac{1}{40}

Hence, The P(Queen ) = 0 , P(spade)= \dfrac{1}{4} and P(5 of heart )= \dfrac{1}{40}

#Learn more

Find the probability of getting a queen from a well shuffled pack of 52 playing cards

brainly.in/question/7548466

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