Question

the kintic energy of 2 mole of a gas speed at 27°in calories

Answer 1

the energy from ................

Answer 2

hey ur answer is,

KE= 3/2nRT
. =3/2x2x2x300
. =1800 cal

here n its number of moles.=2
R is gas constant=2 cal/K
T is temp=300K