Physics, asked by Ashrabxa, 3 months ago

The Kirchhoff's first law  ( \sum i \: = \: 0) and second law  ( \sum iR \: = \: \sum E ) , where the symbols have their usual meanings, are respectively based on
(A) conservation of charge, conservation of momentum
(B) conservation of energy, conservation of charge
(C) conservation of momentum, conservation of charge
(D) conservation of charge, conservation of energy

Answers

Answered by ImSuperHero
1

 \underline {\underline{ \sf{ \maltese \: Question }}} :

The Kirchhoff's first law  ( \sum i \: = \: 0) and second law  ( \sum iR \: = \: \sum E ) , where the symbols have their usual meanings, are respectively based on

 \underline {\underline{ \sf{ \maltese \: Answer }}} :

(D) conservation of charge, conservation of energy

 \underline {\underline{ \sf{ \maltese \: Explaination }}} :

Kirchhoff's   {1}^{st} law or KCL states that the algebraic sum of current meeting at any junction is equal to zero. In other words, we can say that "the sum of all the currents directed towards a junction in a circuit is equal to the sum of all the currents directed away from that junction.

Thus, no charge has been accumulated at any junction i.e., charge is conserved, and hence we can say that KCL  ( \sum i \: = \: 0) is based on conservation of charge.

Kirchhoff's   {2}^{nd} law or KVL states that algebraic sum of potential drops around any closed loop must be zero.

In other words, " around any closed loop, voltage drops are equal to voltage rises". No energy is gained or lost in circulating a charge around a loop. Thus, we can say that KVL is based on conservation of energy

Answered by Jaiganesha
0

The Kirchhoff's first law  ( \sum i \: = \: 0) and second law  ( \sum iR \: = \: \sum E ) , where the symbols have their usual meanings, are respectively based on

(A) conservation of charge, conservation of momentum

(B) conservation of energy, conservation of charge

(C) conservation of momentum, conservation of charge

(D) conservation of charge, conservation of energy

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