Question

The Kp for the reaction N204 = 2NO2 is 640 mm at 775 K. The percentage dissociation of N204 at equilibrium pressure of 160 mm is​

Answer 1

Answer:

ANSWER

Mole before equilibrium N

2

O

4

⇌2NO

2

Mole at equilibrium 1

(1 - x) 2x

K

ρ

=

(1−x)

4x

2

×[

∑n

P

]

Δn

640=

(1−x)

4x

2

(1+x)

160

4=

(1−x)

4x

2

or 1−x

2

=x

2

or 2x

2

=1

∴x

2

=1/2 or x=0.707=70.7%

Explanation:

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