the krishna express leaves vijaywada at 13:45 p.m and reaches sikandrabad at 21:05 p.m if the distance between these two station is 352 km. find the speed of the train.
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Answered by
2
Step-by-step explanation:
speed =distance/time
speed=352/440
speed=4/5
Answered by
4
Total distance= 352 km
Total time =13 : 45+21:05
speed =Distance/ time
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