Question

The Ksp value of Gd (OH)3 is 2.8×10^((−23) , The pH of Gd (OH)3 in saturated solution??

Answer 1

Explanation:

• pOH = -log(oH)
• pH=-log(H)

Answer 2

The Ksp value of Gd (OH)3 is 2.8×10^((−23) , The pH of Gd (OH)3 in saturated solution is 8.48.

Explanation:

The reaction equation for dissociation of $Gd(OH)_{3}$ is as follows.

               $Gd(OH)_{3} \rightarrow Gd^{3+} + 3OH^{-}$

Let us assume that "s" moles of $Gd(OH)_{3}$ gives "s" moles of $Gd^{3+}$ and 3s moles of $OH^{-}$. Therefore, the expression for $K_{sp}$ of this reaction is as follows.

                   $K_{sp} = [s][3s]^{3}$

           $2.8 \times 10^{-23} = 27s^{4}$

                $s^{4} = 0.103 \times 10^{-23}$        

                        s = $1 \times 10^{-6}$

Therefore, concentration of hydroxide ions will be as follows.

               $[OH^{-}]$ = $3 \times 1 \times 10^{-6}$

                              = $3 \times 10^{-6}$

As we know that,    

                  pOH = $-log [OH^{-}]$

                            = 5.52

Since,              pH + pOH = 14

                        pH = 14 - 5.52

                               = 8.48

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