Question

The l and b of a rectangle are (4x+15) and (3x +18) perimeter of the the rectangle is 332 m Find the l and b of the rectangle perimeter
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Answer 1

EXPLANATION:-

Permimeter of rectangle= 2(l+b)

Permimeter of given rectangle= 332

l and b of rectangle=4x+15,3x+18

So 2(4x+15+3x+18)=332

==>2(7x+33)=332

==>14x+66=332

==>14x=332-66

==>14x=266

==>x=266/14

==>x=19

So l=(4x+15)=19×4+15

l=91 m

b=3x+18=3×19+18

b=75 m

Answer 2

Perimeter of the rectangle = 2 × ( l + b ) = 332m

= 2 × [ ( 4x + 15 ) + ( 3x + 18 ) ] = 332m

= 2 × ( 7x + 33 ) = 332m

= 14x + 66 = 332m

IF,

14x + 66 = 332m

THEN,

x = ( 332 - 66 ) ÷ 14

x = 266 ÷ 14

x = 19

LENGTH = 4x + 15

= ( 4 × 19 ) + 15

= 76 + 15

= 91

BREADTH = 3x + 18

= ( 3 × 19 ) + 18

= 57 + 18

= 75

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