Question

the l.c.m and h.c.f of two numbers are 200 and 10 respectively .if one of the two numbers is 40, find the others​

Answer 1

Answer:

The second number is 50

Step-by-step explanation:

Given,

The LCM and HCF of two numbers are 200 and 10 respectively

One number is 40

To find,

The second number

Recall the concept

LCM × HCF = Product of two numbers

Solution:

Let the missing number be 'x'

LCM × HCF = 200 × 10 = 2000

Product of the two numbers = 40x

Since LCM × HCF = the Product of two numbers, we have

40x = 2000

x = $\frac{2000}{40}$ = 50

Hence, the second number is 50

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Answer 2

Given LCM and HCF of two numbers.

$lcm = 200 \\ hcf = 10$

Also, we are given the value of one of the two numbers.

$40$

let the other number be

$x$

We know that

$lcm \times hcf = \: product \: of \: two \: numbers \\ 200 \times 10 = 40 \times x \\ 2000 = 40 \times x \\ x = 2000 \div 40 \\ x = 50$

Therefore, the other number is 50

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