The L.C.M of 64 and another number P is 1216. If the H.C.F is R, the true statement is......(1) R/P=1216/64 (2) R/P=64/1216 (3) R×P=1216/64 (4) P/R=1216×64
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Hi ,
We know that
***************************************
For any two positive integers a and b
HCF( a , b ) × LCM( a , b ) = a × b
***************************************
According to the problem given ,
a = 64 , b = P
LCM ( 64 , P ) = 1216 ,
HCF ( 64 , P ) = R
HCF( 64 , P ) × LCM ( 64 , P ) = 64 × P
R × 1216 = 64 × P
R / P = 64 / 1216
Option ( 2 ) is correct .
I hope this helps you.
:)
We know that
***************************************
For any two positive integers a and b
HCF( a , b ) × LCM( a , b ) = a × b
***************************************
According to the problem given ,
a = 64 , b = P
LCM ( 64 , P ) = 1216 ,
HCF ( 64 , P ) = R
HCF( 64 , P ) × LCM ( 64 , P ) = 64 × P
R × 1216 = 64 × P
R / P = 64 / 1216
Option ( 2 ) is correct .
I hope this helps you.
:)
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