The L.C.M of two numbers is 180 and their H.C.F is 5. If one of the two numbers is 60 . Find the second number.
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Answer:
Given : LCM and HCF of two numbers are 180 and 6.
One number =30
Find : another number =?
Solution :
we know that two numbers product is equal their HCF and LCM product
Let another number =x
x×30=180×6
x=30180×6
x=36
so another number is 36.
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