Question

The L.C.M. of two numbers is 63 and their

H.C.F. is 9. If one of the numbers is 27,

the other number will be​

Answer 1

ANSWER:

• Required number = 21

GIVEN:

• LCM of two numbers = 63.
• HCF of two numbers = 9
• One number = 27

TO FIND:

• Other number.

SOLUTION

Formula:

=> LCM*HCF = Product of two numbers

HERE:

LCM = 63

HCF = 9

First number = 27

Let other number be x.

Putting these values in the formula.

=> 63*9 = 27*(x)

=> (63*9)/27 = x

=> 21 = x

Other number = 21.

Answer 2

$\huge\mathfrak\blue{Answer:}$

Given:

We have been given that the LCM of two numbers is 63 and their HCF is 9. We have also been given that one number is 27.

To Find:

We need to find the other number.

Solution:

As it is given that the LCM of two numbers is 63, HCF is 9 and the first number is 27.

Let the other number be x.

We know that HCF × LCM = Product of numbers.

Substituting values, we have

(9 × 63) = (27 × x)

= 567 = 27x

=> 567/27 = x

=> 21 = x

Therefore, the other number (x) is 21.