Question

The L.C.M of (x-b) and (x-c) is x^2-9 (b>c) then 2b+4c is​

Answer 1

Answer:

I can't answer sorry because i haven't studied it yet sorry

Answer 2

Answer:

-6

Step-by-step explanation:

LCM of two no. is defined as the least common multiple of the two numbers.

Example LCM of two no.  3,5 is 15.

The LCM of (x-b) and (x-c) will be given as  $(x^2-(b+c)x+bc)$

Equating this equation with the result given in the question, we get-

                                     $b+c=0\\b.c=-9$

From the above two relations, we can say that the two no. b and c will be 3 and -3.

As given b>c so,    b = 3 and c = -3.

The answer will be given as :

                                                     $2b+4c\\=2(3)+4(-3)\\=-6$

24 May

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