The L.C.M of x2−4 and x+2 is
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1
Answer:
x
2
−4=(x)
2
−(2)
2
=(x+2)(x−2)
x
2
−5x+6=x
2
−3x−2x+6
=x(x−3)−2(x−3)
=(x−3)(x−2)
L.C.M.=(x−2)(x+2)(x−3)
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