Question

The L.C.M of x3 - 1 and x2 + x + 1 is​

Answer 1

Answer:

x3-1

Step-by-step explanation:

x3-1 = (x-1)(x2+x+1)

Do normal factorization

then you get x3-1

Answer 2

Answer:

The LCM of  $x^3 - 1 \ \ and \ \ x^2 + x + 1$ is $x^3 - 1$

Step-by-step explanation:

• LCM or the least common multiple is the smallest number that is divisible from both the numbers whose LCM is obtained.
• The LCM of 2 and 3 is 6 which is divisible by both 2 and 3.

Step 1 of 1:

• The Factors of the equation  $x^3 - 1$ can be determined as follows.

         $x^3 - 1$

• By the hit and trial method,$x=1$, the equation becomes zero. hence$x-1$ is a factor of the equation.
• Divide the equation   $x-1$ to find the other factors.

         $\frac{x^3-1}{x-1} = x^2 + x + 1$

• Factors of    $x^3 - 1$  are $x-1$ and $x^2 + x + 1$
• Since the other equation is the factor of  $x^3 - 1$. Therefore LCM is   $x^3 - 1$