Question

The l of rectangle is 10m more its b .if the p of rectangle is 80m find the demensions of rectangle​

Answer 1

Answer:

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Answer 2

$\Large{\boxed{\underline{\overline{\mathfrak{\star \: Correct Question :- \: \star}}}}}$

The length of a rectangle is 10 m more than its bredth. if the perimeter of rectangle is 80 m . find the demensions of rectangle.

$\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}$

$\red{\bigstar}$ Length [l]

$\huge\leadsto{\sf\purple{25 \: m}}$

$\red{\bigstar}$ Breadth [B]

$\huge\leadsto{\sf\purple{15 \: m}}$

$\Large{\underline{\underline{\bf{GiVen:-}}}}$

Length of a rectangle is 10 m more than its breadth

So , if we let unknown breadth be "x"

Then our length will become ( x + 10 )

❥ Perimeter of Rectangle ↠ 80m

$\Large{\underline{\underline{\bf{Find:-}}}}$

❥ What's the Dimensions of Rectangle ?

$\Large{\underline{\underline{\bf{SoLuTion:-}}}}$

Here we go !

As we know ,

Perimeter of Rectangle = 2( L + B )

Now,

As according to given

↠ Perimeter of Rectangle = 2 ( x + x + 10)

↠ 80 = 2 ( 2x + 10 )

↠ 80/2 = 2x + 10

↠ 40 = 2x + 10

↠ 2x = 30

↠ x = 15.

Hence,

The Value of x is 15

$\therefore\underline{\boxed{\textsf{The value of x is = {\textbf{15}}}}} \qquad\qquad \bigg\lgroup\bold{Correct \ answer} \bigg\rgroup$

Therefore,

↠ Length

↠ x + 10

↠ 15 + 10 ↠ 25

↠ Breadth = x = 15.

Additional Information :-

❥ Perimeter of Rectangle = 2( L + B )

❥ Perimeter of square = 4 × Side

❥ Perimeter of triangle = AB + BC + CA

❥ Area of Rectangle = L × B

❥ Area of Square = ( side ) ²

❥ Area of Rhombus = Product of Diagonal/2.

❥ Area of Parallelogram = Base × Height.

❥ Area of triangle = 1/2 × base × height .