The Lagrange's remainder after n
terms in the Maclaurin's expansion
of Cos(x) is
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Step-by-step explanation:
The textbook "An introduction to numerical methods and analysis" by James F. Epperson, 2nd edition, page 3:
cos(x)=1−12!x2+14!x4+...+(−1)n(2n)!x2n+(−1)n+1(2n+2)!x2n+2cos(ξx)
So the answer is yes, because the first term for reminder is zero then you can go for the next n.
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Answer:
sorry i really dont now iam sorry
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