English, asked by lanchawangno13, 7 months ago

The lalitudinal value of tropic of cancer is​

Answers

Answered by xXDrunkenBabeXx
21

Answer:approximately 23°27′ N

approximately 23°27′ NTropic of Cancer, latitude approximately 23°27′ N of the terrestrial Equator. This latitude corresponds to the northernmost declination of the Sun's ecliptic to the celestial equator.

Hope it is help you!!

plzz mark me as brainliest..

Answered by ybobby377
0

Answer:

THE ANSWER IS

24 1/2. DEGREE

Similar questions