English, asked by lanchawangno13, 5 months ago

The lalitudinal value of tropic of cancer is​

Answers

Answered by xXDrunkenBabeXx
21

Answer:approximately 23°27′ N

approximately 23°27′ NTropic of Cancer, latitude approximately 23°27′ N of the terrestrial Equator. This latitude corresponds to the northernmost declination of the Sun's ecliptic to the celestial equator.

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Answered by ybobby377
0

Answer:

THE ANSWER IS

24 1/2. DEGREE

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