Question

the lane of 150 m long and 5 m wide is to be paved with tiles of length 20cm and breadth 15 cm. If the cost of the tiles is ₹750 per 1000 tiles, find the cost of the tiles required.​

Answer 1

Answer:

$\boxed{\sf The \;cost \;of \;the\; tiles \;required = Rs18750 .}$

Step-by-step explanation:

Length of the Lane = 150m.

Breadth of the lane = 5m.

Therefore the lane is a rectangular one.

$\sf Area\; of \; tiles \; required = \dfrac{Area\; of \;lane}{Area\; of \;1 \;Tile}$

Area of the Rectangular lane = Length × Breadth

Area of the Rectangular lane = 150 × 5

Area of the Rectangular lane = 750 m²

Length of 1 Tile = 20cm = .20m

Breadth of 1 Tile = 15cm = .15m

Area of 1 Tile = Length of 1 Tile × Breadth of 1 Tile

Area of 1 Tile = .20 × .15

Area of 1 Tile =  0.03 m²

Therefore,

$\sf The\; Total \;number \;of\; Bricks \;required =\dfrac{750}{0.03} = \dfrac{75000}{3} = 25000$

The cost of the tiles is ₹750 per 1000 tiles

Cost of One tile = 750/1000

So, cost of 25000 tiles =  $25000 * \dfrac{750}{1000}$

The cost of the tiles required  = ₹ 18750