Question

The Laplace transform of
sin2t/t​

Answer 1

Step-by-step explanation:

madam this ur answer

step by step

dy/dx= dy/dy / dx/dt

d²y/dx²=d/dt(dt/dx) / dx/dt

x=2cost-cos2t

dx/dt=2sin2t-2sint

y= 2sint- sin2t

dy/dt=2cost-cos2t

dx/dy= cost-cos2t/sin2t-sint

+sin(2t+t/2)(sin(2t-t/2)) / 2cos(2t+t/2)(sin(2t-t/2))

dy/dx=tan(3t/2)

d/dt(dy/dx) / (dx/dt) =3/2 sec²(3t/2) / 2sin2t- 2sint=d²y/dx²

d²y/dx²= 3/4(2/-1)= -3/2

I hope this helps you and if there is a mistake please report I will try to solve ur problem thanks for asking question