the Laplace transforms of e^-5t
Answers
Answered by
0
Answer:
As we all know that,
L { f(t) } = F(s)
L { t*f(t) } = -d( F(s) )/dt
f(t) = e^-5t then Laplace transform is F(s) = 1/(s+5)
t*f(t) = t*e^-5t then the Laplace transform is -d{ 1/(s+5) }/dt
L { t*f(t) } = 1/(s+5)².
Similar questions