Math, asked by rutujajadhav4410, 3 months ago

the Laplace transforms of e^-5t​

Answers

Answered by lailaalif2002
0

Answer:

As we all know that,

L { f(t) } = F(s)

L { t*f(t) } = -d( F(s) )/dt

f(t) = e^-5t then Laplace transform is F(s) = 1/(s+5)

t*f(t) = t*e^-5t then the Laplace transform is -d{ 1/(s+5) }/dt

L { t*f(t) } = 1/(s+5)².

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